Question

Please explain the answer questions no 1 question no 2 explain in photo of ans please explain

Answer 1

For Question 1

Given:

• Chord length = 16 cm

So, AP = PB = 16/2 = 8 cm

• OP = 9 cm

To find:

Length of radius = ?

Solution:

(refer attachment)

In ΔOAP

By Pythagoras theorem,

   OA² = OP² + PA²

⇒ OA² = 9² + 8²

⇒ OA² = 145

⇒ OA = √145

⇒ OA = 12.04 cm

∴ The length of radius = 12.04 cm

For Question 2:

Given:

• Radius = 10 cm
• Length of the chord = 12 cm

To find:

CD = Distance of chord from center = ?

Solution:

Let us consider a point 'D' in the middle of the chord where the line from the center meets the chord.

Now ΔCDA forms a right-angled Triangle.

Here, AD = DB = 12÷2 = 6 cm

Again by Pythagoras Theorem,

    AC² = AD² + CD²

⇒ (10)² = (6)² + CD²

⇒ 100 = 36 + CD²

⇒ CD² = 100 - 36

⇒ CD² = 64

⇒ CD = √64

⇒ CD = 8 cm

∴ Distance of the chord from center = 6 cm

Answer 2

Step-by-step explanation:

ans 1. suppose AB is the chord and OM perpendicular to AB

we know that distance from centre to the chord bisects the circle

so, AM-MB-8cm

OM=6cm

and OA is radius of circle

Now in Tri.AOM

OA^2=OM^2 + AM^2

OA^2=36 + 64

OA^2=100

OA = 10

so, radius of circle is 10 cm

ans 2. Distance of the centre to the chord = AB. CD is perpendiculaar to the chord AB. Perpendicular drawn from the centre of the circle to the chord bisects the chord. Thus, distance of the chord from the centre is 8 cm.