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Answered by
1
X = 280°
Explanation -
const.- draw a line segment PQ from point O ,i.e. PQ || AB || CD
Proof- angle BOQ = 55° ( alternate angle)
angle DOQ = 25° ( " )
angleBOD +angle DOQ +angle BOQ= 360
BOD +25+55=360
BOD =360-80
=280°
Explanation -
const.- draw a line segment PQ from point O ,i.e. PQ || AB || CD
Proof- angle BOQ = 55° ( alternate angle)
angle DOQ = 25° ( " )
angleBOD +angle DOQ +angle BOQ= 360
BOD +25+55=360
BOD =360-80
=280°
Answered by
3
draw a line along be
so angle bdo=90-25
=65°
and angle obd=90-55
=35°
in triangle bod
angle dob=180-(35+65)
=80
so,x=360-80=280°
hope it's helpful and if it is please mark brainliest answer
so angle bdo=90-25
=65°
and angle obd=90-55
=35°
in triangle bod
angle dob=180-(35+65)
=80
so,x=360-80=280°
hope it's helpful and if it is please mark brainliest answer
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