Question

Please explain the given question class VIII​

Answer 1

Answer:

⇢ $\sf{\dfrac{9p^{9} + 2q^{4} r^{3}}{4p^{3} q^{4} r^{4}}}$

Step-by-step explanation:

⇢ $\sf{\bigg(\dfrac{3p^{2} qr^{-2}}{2p^{-1} q^{3}} \bigg)^{2} + (2p^{3} r)^{-1}}$

ㅤ

⇢ $\sf{\dfrac{18p^{9} q^{2} r + 4q^{6} r^{4}}{8p^{3} q^{6} r^{4}}}$

ㅤ

⇢ $\sf{\dfrac{18p^{9} + 4q^{4} r^{3}}{8p^{3} q^{4} r^{4}}}$

ㅤ

⇢ $\sf{\dfrac{9p^{9} + 2q^{4} r^{3}}{4p^{3} q^{4} r^{4}}}$

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Therefore, this is the required answer.

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{\bigg( \frac{3 {p}^{2} q {r}^{ - 2} }{2 {p}^{ - 1} {q}^{3} } \bigg)^{2} + (2 {p}^{3} r) ^{ - 1} = \frac{9 {p}^{9} + 2 {r}^{3} {q}^{4} }{4 {p}^{3} {q}^{4} {r}^{4} }}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies \bigg( \frac{3 {p}^{2} q {r}^{ - 2} }{2 {p}^{ - 1} {q}^{3} } \bigg)^{2} + (2 {p}^{3} r) ^{ - 1} \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies \bigg( \frac{3 {p}^{2} q {r}^{ - 2} }{2 {p}^{ - 1} {q}^{3} } \bigg)^{2} + (2 {p}^{3} r) ^{ - 1} = ?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies \bigg( \frac{3 {p}^{2} q {r}^{ - 2} }{2 {p}^{ - 1} {q}^{3} } \bigg)^{2} + (2 {p}^{3} r) ^{ - 1} \\ \\ \tt: \implies \bigg(\frac{3 {p}^{2 + 1} }{ 2{r}^{2} {q}^{2} } \bigg)^{2} + \frac{1}{2 {p}^{3} r} \\ \\ \tt: \implies \bigg(\frac{3 {p}^{3} }{2 {r}^{2} {q}^{2} } \bigg)^{2} + \frac{1}{2 {p}^{3}r } \\ \\ \tt: \implies \frac{9 {p}^{6} }{4 {r}^{4 } {q}^{4} } + \frac{1}{2 {p}^{3}r } \\ \\ \tt: \implies \frac{9 {p}^{6} \times 2 { p}^{3}r + 4 {r}^{4} {q}^{4} }{4 {r}^{4} {q}^{4} \times 2 {p}^{3}r }$

$\tt: \implies \frac{18 {p}^{9} r + 4 {r}^{4} {q}^{4} }{8 {p}^{3} {q}^{4} {r}^{5} } \\ \\ \tt: \implies \frac{2r(9 {p}^{9} + 2 {r}^{3} {q}^{4} )}{2r(4 {p}^{3} {q}^{4} {r}^{4} ) } \\ \\ \green{ \tt: \implies \bigg( \frac{3 {p}^{2} q {r}^{ - 2} }{2 {p}^{ - 1} {q}^{3} } \bigg)^{2} + (2 {p}^{3} r) ^{ - 1} = \frac{9 {p}^{9} + 2 {r}^{3} {q}^{4} }{4 {p}^{3} {q}^{4} {r}^{4} }}$