Question

please explain the question​

Answer 1

Answer:

D) 9

Step-by-step explanation:

x*y =

$\sqrt{ {x}^{2} + {y}^{2} }$

1*2√2 =

$\sqrt{ {1}^{2} + {(2 \sqrt{2} )}^{2} }$

$\sqrt{1 + (4 \times 2)} = \sqrt{9} = 3$

1* -2√2 = 3

$(1 \times 2 \sqrt{2} )(1 \times - 2 \sqrt{2} ) = 3 \times 3 = 9$

Answer 2

So answer

is d 9

Step-by-step explanation:

The * operation mean you have to take square of 1 value and 2nd value separately and then have to add then as defined in the question so.

$\sqrt{ {1}^{2} + ( {2 \sqrt{2 \: )} }^{2} } \times \sqrt{( {1)}^{2} } + ( {2 \sqrt{2)} }^{2}$

$\sqrt{9} \times \sqrt{9}$

$3 \times 3$

$9$