please explain the step
3*3k-1/2
3k+1-1/2
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collinear means that all points lie on the same straight line ,
Hence ,slope of AB= stop of AC
slope of ABis = (k-2 )-(k-7)/(3k-1)-k = 5/(2k-1)
slope of AC= (k-2) -(-k-2)/(3k-1)-(k-1)
= 2k/2k=1
hence slope AB should be 1
5/2k -1=1
2k-1=5
2k=6
k=3
the value of k is 3
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