please explain the sum
ans : e
Attachments:
Answers
Answered by
1
As per given conditions we get
Recipe=4A+7B
These substances are to be taken by weight but they were taken by volumes.
117cm3 of A=151cm3 of B
Difference =151-117=34
Error in the percentage of the weight A=
34/117×100=3400/117=29.05%
Therefore error in the weight of percentage of weight A=29.05%
Recipe=4A+7B
These substances are to be taken by weight but they were taken by volumes.
117cm3 of A=151cm3 of B
Difference =151-117=34
Error in the percentage of the weight A=
34/117×100=3400/117=29.05%
Therefore error in the weight of percentage of weight A=29.05%
Similar questions