please explain the sum
ans e)57
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D+V+SE+SA+Y=39*5=195-----(1)
D=Y+7
V=Y+9
SE=D+Y=2Y+7
SE+SA=110
SUBSTITUTE ABOVE VALUE IN (1)
110+Y+7+Y+9+Y=195
3Y=69
Y=23
SE=46+7=53
SA=110-53=57
D=Y+7
V=Y+9
SE=D+Y=2Y+7
SE+SA=110
SUBSTITUTE ABOVE VALUE IN (1)
110+Y+7+Y+9+Y=195
3Y=69
Y=23
SE=46+7=53
SA=110-53=57
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