Question

Please explain this .

Answer 1

Hi there.... :)

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Let's refresh some ground concepts as it is an essential in answering SHM probs...

SHM⇒ Simple Harmonic Motion.

It is a special kind of periodic motion (i.e; wave motion) where a particular condition is satisfied...   the displacement from mean position is directly proportional to the restoring force (more precisely the acceleration) at that point.

S∝ -a (-ve sign indicates opposite direction)

S=displacement    a= acceleration

Now,as SHM is understood as a periodic motion, we can reference it visually by considering the projection of a particle in uniform circular motion on respective axes.......

this might be a bit too much to comprehend but.... try to understand.... Refer to the pic attached to know more about how SHM can be seen as UCM projection

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You need to understand what phase is...

Phase[Ф] = the initial angle the particle makes with the reference axis. i.e; from where the particle starts its SHM

it is merely just an angle added to wt in the general equation.

y = A sin(wt)          [ particle with no initial phase ]

y = A sin(wt ± Ф)   [ particle with initial phase Ф  ]

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Now... coming to the question....

two shm equations are given and we can see that only the amplitude is different. all the other parameters are same.... even phase.... hence we can state tht the phase difference b/w the two shms is zero....

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Cheers :)