Question

please explain this guys ....help​

Answer 1

Answer:

8100 m

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Answer 2

Answer:

option (c) is the correct answer.

Explanation:

Acceleration a=−0.5m/s²

Speed v=90km/h=25m/s

Using equation of motion,

v=u+at

Where,

v = final velocity

u = initial velocity

a = acceleration

t = time

Put the value into the equation

Finally train will be rest so, final velocity,v=0

0=25−0.5t

25=0.5t

t= 25/0.5

t=50 sec

Again, using equation of motion,

S=ut+1/2at²

Where, s = distance

v = final velocity

u = initial velocity

a = acceleration

t = time

Put the value into the equation

Where S is distance travelled before stop

s=25×50− 1/2×0.5×(50)²

s=625 m