Question

Please explain this in detail​

Answer 1

Answer:

force applied on mass m1, then acceleration

⇒12=Fm2

If force applied on mass m2, then acceleration

3=Fm2

When same force is applied on m2−m1 Then,

acceleration a=Fm2−m1=FF3−F12

=4m/s2

Answer 2

Explanation:

Case 1:

F = m1×12

M1 = F/12

Case 2:

F = m2 ×10

m2 = F /10

Case 3:

F = ( m2-m1) a'

F = (F/60)a'

a' = 60 m/s2

Case 4:

F = (m1 + m2) a"

F = (11F/60)a"

a"= 60/11 m/s2