Question

Please Explain this Numerical :-.

Calculate the weight of quicklime formed when 400g of calcium carbonate is heated. [ Atomic weight : Calcium = 40, Oxygen = 16 ; Carbon = 12 ]​

Answer 1

Answer:

224 gm

Explanation:

GIVEN,

Calcium = 40

Oxygen = 16

Carbon = 12

CaCO3 = 40 + 12 + 3 x 16

=> 52 + 48

=> 100g

CaO = 40 + 16 = 56

Now we know the reaction is,

CaCO3 ---> CaO + CO2

100g ----> 56

Now,

When CaCO3 is 400g

Therefore,

Let the amount of Calcium oxide or Quicklime be x.

CaCO3 ----> CaO + CO2

400g ----> x

$= > \frac{400 \times 56}{100} = 224gm$

Hope the answer helps you.

Answer 2

Answer:

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