Question

please explain this Q5

Answer 1

In triangle AOB,
OA = OB
Therefore, angle OBA = angle OAB
Now ,
Angle OBA + angle OAB + angle AOB= 180°
angle OBA + angle OAB = 180° - 100°
2 angle OAB = 80° (Since , angle OAB = angle OBA)
angle OAB = 40°
Now, AT is a tangent
Thus , AngleOAT = 90° [line segment joining the center to the point of contact of a tangent is perpendicular]
Therefore, angle OAB + angle BAT = 90°
angle BAT = 90°- 40°
Hence , Angle BAT = 50°
Hope this helps you.....