Question

please explain this question ​

Answer 1

Answer:

l

❤THIS IS YOUR REQUIRE ANSWER ❤

Explanation:

$displacement. \: s = 10 + {4.9t}^{2} \\ velocity \: . \: v = \frac{ds}{dt} = 10 + 4.9t \\ (1) = intial \: velocity \\ (i.e. \: velocity \: \: t = 0) \: = 10 + 0 \\ \\ = 10 {ms}^{ - 1} \\ \\ (2) = velocity \: at \: (t) =3 \: second \: is \\ v = 10 + 2 \times 4.9 \times 3 = 39.4 {ms}^{ - 1} \\ \\ (3) = acceleration \: \\ a = \frac{dv}{dt} = \frac{d}{dt} (10 + 9.8t) \\ = 9.8 {ms}^{ - 2} < ans >$

Answer 2

Answer:

I can do....... ➡️➡️➡️

Explanation:

mmm