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This is the question related to conservation of angular momentum.
Metallic circular wheel of mass M. Let us take it as a Ring or disc.
Initial Radius = R1
Final radius = R2. = R1 + 0.2/100 R1 = R1* 1.02
Let k be a constant.
Moment of inertia = I1 = k * M R1² , initial
= I2 = k M R2² , final
Let us say initial angular velocity = ω1.
Final angular velocity is = ω2.
So Ang. Momentum = I1 * ω1 = I2 * ω2
So ω2/ω1 = I1 /I2 = R1²/R2² = 1/1.02² ≈ 1 - 0.04
ω2 / ω1 ≈ 0.96
Answer is (4) decreases by 0.04 %
Metallic circular wheel of mass M. Let us take it as a Ring or disc.
Initial Radius = R1
Final radius = R2. = R1 + 0.2/100 R1 = R1* 1.02
Let k be a constant.
Moment of inertia = I1 = k * M R1² , initial
= I2 = k M R2² , final
Let us say initial angular velocity = ω1.
Final angular velocity is = ω2.
So Ang. Momentum = I1 * ω1 = I2 * ω2
So ω2/ω1 = I1 /I2 = R1²/R2² = 1/1.02² ≈ 1 - 0.04
ω2 / ω1 ≈ 0.96
Answer is (4) decreases by 0.04 %
kvnmurty:
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this is related to conservation of angular momentum
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