Question

please explain this question. ​

Answer 1

Given : Neeraj Chopra Jawline Throw

To Find : Shape of Trajectory

Solution:

Shape of Trajectory  is Parabola

in  ax² + bx  + c = 0

if a < 0 then parabola open down ward

if one zero is negative of  other than  b = 0

hence no linear term

and constant is  positive  as height can not be negative

x² - x  - 12 = 0

=> x² - 4x + 3x - 12 = 0

=> x( x- 4) + 3(x - 4) = 0

=> (x - 4)(x + 3) = 0

=>  x= 4 , -3

intersect x axis at 2 distinct points

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