Question

please explain this question. don't just write answer and go. you will be reported . please explain ​

Answer 1

Answer:

least count of vernier callipers=

$\frac{ value \: of \: one \: main \: scale \: division}{total \: number \: of \: division \: on \: vernier \: scale}$

value of 1 main scale division=1/n mm

total no of division on vernier scale=n

so L.C

=1/n÷n

1/n^2

Answer 2

Explanation:

this is your answer mate⬆⬆⬆⬆