Question

Please explain this question I don't want the answer.

a 8000 kg engine pulls a train of 5 wagons, each of 2000 kg, along a horizontal track. If the engine exerts a force of 40000 N and the track offers a frictional force of 5000 N, then calculate:

a)the net acceleration force,
b)the acceleration of the train,
c)the force of wagon 1 on wagon 2​

Answer 1

Given parameters

Mass of the engine (M) = 8000 kg

Number of wagons = 5

Mass of the wagons (m) = 2000 kg

Force exerted by the engine (F ) = 40000 N

Frictional force offered by the track (Ff) = 5000 N

(a) Net force (Fa) = F – Ff

Fa = 40000 N – 5000 N

Fa = 35000 N

(b.) Let us consider the acceleration of the train to be a m/s2

Acceleration is the ratio of net acceleration force by mass, i.e.

a = Fa/m

Where m is the mass of the train, it can be calculated as follows

The total mass of the train (m) = Mass of the engine + (Mass of the wagons  × Number of wagons)

m = 8000 + (5 × 2000)

m = 18000 kg

Acceleration of the train (a) = 35000/18000

a = 1.944m/s2

(c.) F21 = m4w × a

F21 = Force applied on Wagon 2 by Wagon 1

m4w = mass of 4 wagons

a = acceleration of the train

The force of wagon 1 on wagon 2 = Force of wagon 2 on wagon 1

⇒ (4 × 2000 × 1.944)

= 15552 N

∴ The force of wagon-1 on the wagon-2 is 15552 N.

Answer 2

Answer:

एक 8000 किग्रा का इंजन एक क्षैतिज ट्रैक के साथ 5 वैगनों, प्रत्येक 2000 किग्रा की एक ट्रेन को खींचता है। यदि इंजन 40000 N का बल लगाता है और ट्रैक 5000 N का घर्षण बल प्रदान करता है, तो गणना करें:

ए) शुद्ध त्वरण बल,

बी) ट्रेन का त्वरण,

ग) वैगन 2 पर वैगन 1 का बल

Explanation:

you mai have the explanation