Math, asked by ved4129, 3 months ago

please explain this question spammers will be reported​

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Answers

Answered by payushi9589
2

Answer:

1234321 = (4444)² / ( 1+2+3+4+3+2+1 )

123454321 = (55555)² / (1+2+3+4+5+4+3+2+1)

12345654321 = (666666)² / (1+2+3+4+5+6+5+4+3+2+1)

Step-by-step explanation:

Hope this helps

Answered by AghilaCC
1

Answer:

1234321 =  \frac{ {(4444)}^{2} }{1 + 2 + 3 + 4 + 3 + 2 + 1}  \\ 123454321 =  \frac{ {(55555)}^{2} }{1 + 2 + 3 + 4 + 5 + 4 + 3 + 2 + 1}  \\ 12345654321 =  \frac{ {(666666)}^{2} }{1 + 2 + 3 + 4 + 5 + 6 + 5 + 4 + 3 + 2 + 1}

Step-by-step explanation:

In the first and second patterns the middle number n is written n times and it's square is taken as numerator.

ie, in 121, 2 is the middle number. It is written 2 times (that's what I meant by the underlined). The denominator is the sum of the digits of that number.

ie, in 121, 1+2+2

Just like this, we can complete the pattern

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