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any number which has 0 and 5 at last is divisible by 5
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a) for the number to be divisible by 3 , the sum of the digits must be divisible by 3
since the sum is 6+x and 6 is divisible by 3 hence x= 0
b) for the no. to be divisible by 4, the last two digits must be divisible by 4
since the last two digits are x8 and 8 is divisible by 4 so the smallest digit is 0
d for the no. to be divisible by 5 , the no. must end with 0 and 5 so smallest digit is 0
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