Please explain what the question means. I would solve it by myself. Thankss! :D
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According to question there is a particle which is moving on curve 12y=x³ and at time t its x co-ordinate is 10 and you need to find which one is greater dy/dt or dx/dt for this you need to differentiate 12y=x³ wrt to t and find rates of x and y coordinates.
12dy/dt=3x²dx/dt if dy/dt is horizontal speed (y axis ) and dx/dt ( x axis) 12Vy=3(100)VX
Vy=300/12VX
so particle moves faster along y coordinate i.e, dy/dt>dx/dt.
12dy/dt=3x²dx/dt if dy/dt is horizontal speed (y axis ) and dx/dt ( x axis) 12Vy=3(100)VX
Vy=300/12VX
so particle moves faster along y coordinate i.e, dy/dt>dx/dt.
Divyankasc:
OOOhhh
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12y = x³
differentiate wrt time
12dy/dt = 3x²dx/dt
dy/dt = speed of particle in y -axis = Vy(let)
dx/dt = speed of particle in x -axis = Vx(let)
e.g 12Vy = 3x²Vx
at x = 10
12Vy = 3(10)²Vx
4Vy = 100Vx
Vy = 25Vx
here you can see that particle speed in y axis is 25 times greater then x -axis .
so,
particle faster in y -axis
so, option ( B) is correct
differentiate wrt time
12dy/dt = 3x²dx/dt
dy/dt = speed of particle in y -axis = Vy(let)
dx/dt = speed of particle in x -axis = Vx(let)
e.g 12Vy = 3x²Vx
at x = 10
12Vy = 3(10)²Vx
4Vy = 100Vx
Vy = 25Vx
here you can see that particle speed in y axis is 25 times greater then x -axis .
so,
particle faster in y -axis
so, option ( B) is correct
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