Please explain why we have done this question this way...
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Because ∆G values are additive for particular reactions. We can add or subtract values of ∆G for two or more reactions to get ∆G of target reaction.
If we talk about this question, we have three given equations and their ∆G values and we have to find ∆G values for the 4th reaction
i.e. 2ZnS+3 O2----> 2ZnO +2 SO2
if we have a look at given reactions Zns is in the second reaction but it's in the product part so we will take -∆G2 and other two reactions have O2 in reactant (as required), hence it will taken as +∆G1 and +∆G3
so finally it becomes
∆G4= -∆G2+∆G1+∆G3
hope it helps
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