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A copper rod of diameter 1cm and length 8cm is drawn into a wire of length 18m of uniform thickness. Find the thickness of the wire.
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= Volume of rod = volume of wire
= pie R square H = pie r square h
= R square H = r square h
= 0.5 square 8 = r square 1800
= 0.25 × 8. = r square 1800
= r square. = 0.25 × 8 / 1800
= r. = 1 / 30
= d. = 1 / 15
= thickness = 0.67 mm approx.
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= pie R square H = pie r square h
= R square H = r square h
= 0.5 square 8 = r square 1800
= 0.25 × 8. = r square 1800
= r square. = 0.25 × 8 / 1800
= r. = 1 / 30
= d. = 1 / 15
= thickness = 0.67 mm approx.
please mark as brainliest if you like so
JessicaMalik:
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volume of copper rod = volume of wire
volume of copper rod
copper rod with the form of cylinder with diameter of rod = 1
so radius R = 1/2 cm
length = height = 8cm
volume of rod =πr^2 h
= π x 1/4 x 8
= 2π
height = 18 x 100 = 1800
volume of wire = πr^2 h
=πr^2 x 1800
= 1800πr^2
1800πr^2 = 2π
1800 r^2 = 2
r^2 = 2/1800
r^2 = 1/900
when square shifte to opp. side it changes to square root
r = √1/900
r= √1/30 x 30
r= √1/30^2
r=1/30
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volume of copper rod
copper rod with the form of cylinder with diameter of rod = 1
so radius R = 1/2 cm
length = height = 8cm
volume of rod =πr^2 h
= π x 1/4 x 8
= 2π
height = 18 x 100 = 1800
volume of wire = πr^2 h
=πr^2 x 1800
= 1800πr^2
1800πr^2 = 2π
1800 r^2 = 2
r^2 = 2/1800
r^2 = 1/900
when square shifte to opp. side it changes to square root
r = √1/900
r= √1/30 x 30
r= √1/30^2
r=1/30
mark as brainlist
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