Physics, asked by Wafamol3966, 12 hours ago

Please explain with working
During a paintball fight, a paint pellet of mass 150g hits a stationary target with a speed 220m/s . It takes 0.025s from the moment the pellet comes into contact with the wall until it flattens onto the wall. What is the force exerted as a result of the paintball 'splat'? *
1.3 x 10^3 N
33 N
1.3 x 10^6 N
33 x 10^3 N

Answers

Answered by snehasneha3431
1

Answer:

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Answered by heena012131
3

Answer:

The force exerted is 1.3*10^3N

Explanation:

Mass of the paint pellet=150 g =0.15 kg

The initial velocity with which it hots the target is u=220m/s,

The time taken from the moment the pellet comes into contact with the wall until it flattens , t=0.025s.

Final velocity v=0\\

The acceleration with which the the paint ball comes is a=\frac{v-u}{t}=\frac{0-220}{0.025}=8800 m/s^2\\.

Hence the force exerted as a result of paint ball 'splat ', F=ma = 0.15*8800=1320N1.3*10^3 N

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