please explain your answer
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EXPLANATION
- GIVEN
Body is vertically upward with a velocity = u
after 1 and 7 second it cross reference point
at a height h
TO FIND VALUE OF U.
As we know that body is project upward
we can apply,
newton 2nd law of kinematics
h = ut - 1/2gt^2
for 1 seconds
h = u(1) - 1/2 g
h = u - g/2 .... (1)
for 7 seconds
h = u(7) - 1/2 g (7) ^2
h = 7u - 49g / 2 .... (2)
from equation (1) and (2)
we get,
u - g/2 = 7u - 49g/2
24g = 6u
4g = u
g = 10 m/s^2 [GIVEN]
Therefore,
u = 40 m/s = ANSWER
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