please explian it fast
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let z=1-i root3 /1-i root3
z =1+i(0)=x+iy
x=1,y=0
argument of z=tan inverse of(y/x)
=tan inverse of (0)
=0
z =1+i(0)=x+iy
x=1,y=0
argument of z=tan inverse of(y/x)
=tan inverse of (0)
=0
gsnarayana:
option is e
Answered by
1
bro directly the question say find the argument of 1 means 1+0i so y=0 & x= 1. and tan^-1 (0/1) = 0 so e is correct option
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