Question

please factories it​

Answer 1

Step-by-step explanation:

i) 8x2y3-x5 = (x2)(8y3-x3)

ii) x4y4-xy = (xy)(x3y3-1)

Answer 2

1.

$8x ^{2} y ^{3} - {x}^{5} \\ = {x}^{2} (8 {y}^{3} - { x}^{3} ) \\ = {x}^{2} (( {2y})^{3} - {x}^{3} )$

Using,

${x}^{3} - {y}^{3} = (x - y)( {x}^{2} + {y}^{2} + xy)$

We get,

${x}^{2} (2y - x)(4 {y}^{2} + {x}^{2} + 2xy)$

2.

${x}^{4} {y}^{4} - xy \\ = xy( {x}^{3} {y}^{3} - {1}^{3} ) \\ = xy((xy) ^{3} - {1}^{3} ) \\ = xy(xy - 1)(x ^{2} y ^{2} + 1 + xy)$