Question

Please factorise: 8/27x^3 +2/3x^2y+1/2xy^2+1/8y^3​

Answer 1

Answer:

i am not sure but here

Step-by-step explanation:

Given: The term 8/27x^3 - 1/8y^3

To find: Factorise the given term.

Solution:

Now we have given the term 8/27x^3-1/8y^3

We can rewrite it as:

              8/27x^3-1/8y^3 = (2x/3)^3 - (y/2)^3

Now we know the formula:

              (a^3 - b^3) = (a - b)(a^2 + ab + b^2)

So applying this for given term, we get:

              (2x/3)^3 - (y/2)^3 = (2x/3 - y/2) x ((2x/3)^2 + (2x/3)(y/2) + (y/2)^2)

                                           = (2x/3 - y/2) x (4x^2/9 + xy/3 + y^2/4)