Math, asked by satyalgoma, 1 month ago

please factorise it

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Answered by abhi52329
0

Answer:

( \cot( \alpha )  + 2 \sec( \alpha ) ) \times (2 \cot( \alpha )  -  \sec( \alpha ) )

Step-by-step explanation:

2cot^{2}  \alpha    -   \cot( \alpha ) \sec( \alpha )  + 4\cot( \alpha )  \sec( \alpha) \  - 2  \sec ^{2} ( \alpha )

 \cot( \alpha ) (2 \cot( \alpha )  -  \sec(  \alpha ) )  + 2 \sec(  \alpha ) (2 \cot( \alpha ) -  \sec( \alpha )  )

( \cot( \alpha )  + 2 \sec( \alpha ) ) \times (2 \cot( \alpha )  -  \sec( \alpha ) )

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