Question

please factorise it
fast​

Answer 1

$it \: is \: in \: the \: form \: of \: a {}^{3 } + b {}^{3} + c {}^{3} \\ \\ if \: a {}^{3} + b {}^{3 } + c {}^{3} \: = 3abc \: \: \\ \\ then \: \: a + b \: + c \: = 0 \\ \\ here \: 2x - y + y - 3z + 3z - 2x = 0 \\ \\ so \: \: (2x - y) {}^{3} \: + (y - 3z) {}^{3} + (3z - 2x) {}^{3} \\ \\ = 3(2x - y)(y - 3z)(3z - 2x)$