please Factorise it :p⁴-256
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its of 20 pts
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p⁴-256
=(p²)²-(16)². (a-b)formula
=(p²-16)²
=(p²+16)(p²-16)
=(p²)²-(16)². (a-b)formula
=(p²-16)²
=(p²+16)(p²-16)
Answered by
7
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p⁴-256
=(p²)²-(16)²
=(p²+16)(p²-16){because a²-b²=(a+b)(a-b)}
=(p²+16)[p²-(4)²]
=(p²+16)(p+4)(p-4).
This is your ans.
but if imaginary part is allowed,then we can solve (p²+16)=0
p²=-16
p=√-16
p=±4i
i.e.(p²+16)=(p+4i)(p-4i)
Therefore the ans.becomes...
p⁴-256=(p²+16)(p+4)(p-4)
=(p+4)(p-4)(p+4i)(p-4i).
Hope it helps u...
:-)
p⁴-256
=(p²)²-(16)²
=(p²+16)(p²-16){because a²-b²=(a+b)(a-b)}
=(p²+16)[p²-(4)²]
=(p²+16)(p+4)(p-4).
This is your ans.
but if imaginary part is allowed,then we can solve (p²+16)=0
p²=-16
p=√-16
p=±4i
i.e.(p²+16)=(p+4i)(p-4i)
Therefore the ans.becomes...
p⁴-256=(p²+16)(p+4)(p-4)
=(p+4)(p-4)(p+4i)(p-4i).
Hope it helps u...
:-)
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