please factorise
Answers
Answered by
1
(a³-b³) - a - b
= [(a-b)(a²+b²+ab)]-a-b
= (a-b)(a²+b²+ab)-a-b
= (a-b)(a²+b²+ab)-1(a-b)
= (a-b)(a²+b²+ab-1)
= [(a-b)(a²+b²+ab)]-a-b
= (a-b)(a²+b²+ab)-a-b
= (a-b)(a²+b²+ab)-1(a-b)
= (a-b)(a²+b²+ab-1)
Apshrivastva:
wrong
again wrong
if u take -1 common in (a-b) the you get -1(a+)
if you take -1 common in (a-b) then you get -1(a+b)
Answered by
0
Hey.Here is your answer u r looking for
(a^3-b^3)-a-b
(a-b)(a^2+ab+b^2)+1(a-b)
(a-b)(a^2+ab+b^2+1)
(a^3-b^3)-a-b
(a-b)(a^2+ab+b^2)+1(a-b)
(a-b)(a^2+ab+b^2+1)
Similar questions