Question

Please factorise the below questions and show full working X*+2x/x*-3x X*-3x/x*-2x-3 Pic is below if u don’t understand

Answer 1

Question:- 1)

$\bf \frac{ {x}^{2} + 2x}{ {x}^{2} - 3x }$

solution:-

Now take x as a common

$\bf \: \frac{x(x + 2)}{x(x - 3)}$

X is cancel we out, we get

$\bf \frac{x + 2}{x - 3}$

$\bf \: \green{answer = \frac{x + 2}{x - 3} }$

Question:- 2)

$\bf \: \frac{ {x}^{2} - 3x }{ {x}^{2} - 2x - 3 }$

solution:-

Factories the denominator , we get

$\bf \: \frac{x(x - 3)}{ {x}^{2} - 3x + x - 3}$

$\bf \: \frac{x( {x} - 3)}{x(x - 3) + 1(x - 3)}$

$\bf \: \frac{x( {x} - 3)}{(x + 1)(x - 3)}$

Now x - 3 is cancel out we get

$\bf \: \frac{x}{x + 1}$

$\bf \red{answer \: = \: \frac{x}{x + 1} }$

Question:- 3)

$\bf \: \frac{ {x}^{2} + 4x}{2 {x}^{2} - 10x}$

solution:-

Take a common

$\bf \: \frac{x(x + 4)}{2x(x - 5)}$

X is cancel out

$\bf \: \frac{x + 4}{2(x - 5)}$

$\bf \: \orange{answer = \frac{x + 4}{2(x - 5)} }$

Answer 2

$\bf \huge \green{answer}$

1)Answer:-

$\bf \red{ \implies \: \frac{ {x}^{2} + 2x }{ {x}^{2} - 3x} }$

$\bf \red{ \implies \: \frac{x(x + 2)}{x(x - 3)} }$

$\bf \red{ \implies \: \frac{x + 2}{x - 3}}$

2)Answer:-

$\bf \pink{ \implies \: \frac{ {x}^{2} - 3x }{ {x}^{2} - 2x - 3} }$

factories the denominator

$\bf \pink{ \implies \frac{x(x - 3)}{ {x}^{2} + 2x - 3x - 3} }$

$\bf \pink{ \implies \frac{x(x - 3)}{(x + 1)(x - 3)}}$

$\bf \pink{ \implies \frac{x}{x + 1}}$

3)Answer:-

$\bf \purple{ \implies \: \frac{ {x}^{2} + 4x }{ {2x}^{2} - 10x}}$

$\bf \purple{ \implies\frac{x(x + 4)}{2x(x - 5)}}$

$\bf \purple{ \implies \: \frac{x + 4}{2(x - 5)}}$