Please factorise this .....
It may help you and me.....
because on 28th it is maths paper. So please answer it
Attachments:
Answers
Answered by
1
4n^2 +5n - 636 = 0
=> 4n^2 - 48n +53n- 636 = 0
=> 4n( n - 12) + 53(n-12) = 0
=> (4n +53)(n-12) = 0
n = 12 and - 53/4
=> 4n^2 - 48n +53n- 636 = 0
=> 4n( n - 12) + 53(n-12) = 0
=> (4n +53)(n-12) = 0
n = 12 and - 53/4
gaurav2013c:
??
this is correct answers but thanks u answered it...
Yeah.........
i am doing it
if u r in class 10
Yeah...
exercise 5.3
question no.4
follow me if u r in class 10
we will do practice together....
Answered by
1
HI,
=========
Step 1: Factor left side of equation.
(4n+53)(n−12)=0
Step 2: Set factors equal to 0.
4n+53=0 or n−12=0
n=
or n=12
Answer:
n= or n=12
============
Hope helped!!
=========
Step 1: Factor left side of equation.
(4n+53)(n−12)=0
Step 2: Set factors equal to 0.
4n+53=0 or n−12=0
n=
Answer:
n=
============
Hope helped!!
kaha se tepa
saaf saaf pata chal raha hai
?? are you crazy?
it's a self written answer.. don't insult me for answwering your question..at least be grateful im answering it..
Yaa bro you have written it by own
Be cool bro :)
Similar questions