Question

please factorise this question

Answer 1

Answer:

x^2-y^2-2y-1

x^2-1-y^2-2y

(x^2-1^2)-y(y+2)

(x-1)(x+1)-y(y+2)

Answer 2

Answer:

Given equation:-

x^2-y^2-2y-1

Solution:-

${x}^{2} - {y }^{2} - 2y - 1 \\ = {x}^{2} - ( {y}^{2} + 2y + 1) \\ = {(x)}^{2} - ( {(y)}^{2} + 2 \times y \times 1 + {1}^{2} ) \\ = {(x)}^{2} - {(y + 1) }^{2} \\ = (x + y + 1)(x - y - 1)$