Question

please factorise this question​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

$Identity - \\ \\ \\</p><p></p><p>a^3+b^3+c^3 -3abc = (a+b+c) (a^2+b^2+c^2-ab-bc-ca)\\ \\ \\</p><p></p><p>8x^3+y^3+27z^3-18xyz= \\ \\ \\</p><p></p><p>(2x)^3 +(y)^3 +(3z)^3 -3(2x ×y×3z)\\ \\ \\</p><p></p><p>= (2x+y+3z)[(2x)^2 +(y)^2 +(3z)^2 -(2x ×y) - (y× 3z)- (2x × 3z)]\\ \\ \\</p><p></p><p>= (2x+y+3z)(4x^2+y^2+9z^2-2xy -3zy -6xz)$