PLEASE FACTORISE THIS SUM : a^3x^3-3a^2bx^2+3ab^2x-b^3
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Now,
a³x³ - 3a²bx² + 3ab²x - b³
= (ax)³ - 3(ax)²b + 3axb² - b³
= (ax - b)³,
using the identity
(x - y)³ = x³ - 3x²y + 3xy² - y³
= (ax - b) (ax - b) (ax - b),
which is the required factorization.
#MarkAsBrainliest
Now,
a³x³ - 3a²bx² + 3ab²x - b³
= (ax)³ - 3(ax)²b + 3axb² - b³
= (ax - b)³,
using the identity
(x - y)³ = x³ - 3x²y + 3xy² - y³
= (ax - b) (ax - b) (ax - b),
which is the required factorization.
#MarkAsBrainliest
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