please factorize : a4+3a2+4
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Hey!!!!
We have
=> a⁴ + 3a² + 4 = 0
Here let a² = x
=> x² + 3x + 4 = 0
=> x² + 4x - x + 4 = 0
=> x(x + 4) - (x + 4) = 0
=> (x - 1)(x + 4) = 0
Thus x = 1 or x = - 4
Then a² = 1 or a² = -4
=> a = 1 or a = -1 or a = √-4
Hope this helps
We have
=> a⁴ + 3a² + 4 = 0
Here let a² = x
=> x² + 3x + 4 = 0
=> x² + 4x - x + 4 = 0
=> x(x + 4) - (x + 4) = 0
=> (x - 1)(x + 4) = 0
Thus x = 1 or x = - 4
Then a² = 1 or a² = -4
=> a = 1 or a = -1 or a = √-4
Hope this helps
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