please factorize it quickly
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Solution :
Now, 32x²/y + 108y²/x
= 4 {8x³/(xy)} + 4 {27y³/(xy)}
= 4/(xy) (8x³ + 27y³)
= 4/(xy) {(2x)³ + (3y)³}
= 4/(xy) (2x + 3y) {(2x)² - (2x * 3y) + (3y)²}
= 4/(xy) (2x + 3y) (4x² - 6xy + 9y²) ,
which is the required factorization.
Identity Rules :
- (a + b)² = a² + 2ab + b²
- (a - b)² = a² - 2ab + b²
- (a + b)³ = a³ + 3a²b + 3ab² + b³
- (a - b)³ = a³ - 3a²b + 3ab² - b³
- a³ + b³ = (a + b) (a² - ab + b²)
- a³ - b³ = (a - b) (a² + ab + b²)
Answered by
1
Answer:
4x/y(2x+3y)(4x²+9y²-6xy)
Explanation:- hope it will be helpful to you
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