Question

please fast........... ​

Answer 1

$\LARGE{\bf{\underline{\underline{Solution:-}}}}$

Given:

Base of triangle = 15 cm

Area of triangle = 60 cm²

To Find:

• Altitude of triangle

Formula:

Altitude = 2$\dfrac{Area}{Base}$

So,

Altitude of triangle = $2(\sf\cancel \dfrac{60}{15})$

= 2 (4)

= 8 cm

Answer:

Altitude of triangle = 8 cm

____________________________

More Formulas to know:

• Area of triangle = $\dfrac{bh}{2}$

• Perimeter of triangle = a + b + c

b = Base

h = Height

a, c = Side

_____________________________

Answer 2

Answer:

Base of triangle = 15 cm

Area of triangle = 60 cm²

To Find:

• Altitude of triangle

Formula:

Altitude = 2\dfrac{Area}{Base}BaseArea

So,

Altitude of triangle = 2(\sf\cancel \dfrac{60}{15})2(1560)

= 2 (4)

= 8 cm

Answer:

Altitude of triangle = 8 cm

____________________________

More Formulas to know:

• Area of triangle = \dfrac{bh}{2}2bh

• Perimeter of triangle = a + b + c

b = Base

h = Height

a, c = Side

_____________________________