Question

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Answer 1

Answer:

Rs.2,21,184

Step-by-step explanation:

given

Present cost = rs. 2,50,000

Rate of depreciation = 4%

Time = 3 years

The present cost is the principal (p)

The depreciation rate is the rate (r)

The number of years is the time (n)

Formula for finding depreciated value= p(1 - r/100)^n

So by using the formula we get

=2,50,000( 1 - 4/100)^3

=2,50,000(96/100)^3

=2,50,000×96×96×96/100×100×100

=rs. 2,21,184

So the cost of the machine after three years at depreciation value of 4% is Rs. 2,21,184

Answer 2

Question:

The cost of a machine is 2,50,000 it depreciates at a rate of 4% per annum. Find the cost of machine after 4 years

Given :

The cost of a machine is ₹ 250000. It depreciates at the rate of 4% per annum.

$\hookrightarrow \textsf{Principal(P)=2,50,000}$

$\hookrightarrow\texttt{Time(n) = 3 years}$

$\hookrightarrow \textsc{Rate(R)=4\%}$

To Find:

The cost of the machine after 3 years.

Formula Used:

$A = P(1+\frac{R}{100})^n$

Solution:

$\textsf { We Have} : \\ \\\hookrightarrow \textsf{Principal(P)=2,50,000} \\ \\ \hookrightarrow\texttt{Time(n) = 3 years} \\ \\ \hookrightarrow \textsc{Rate(R)=4\%}$

Therefore by using the Formula

$A = P(1+\frac{R}{100})^n\\\\\\\to A=250000(1-\frac{4}{100})^3\\\\\\\to A=250000(1-\frac{1}{25})^3\\\\\\\to A= 250000(\frac{25-1}{25})^3\\\\\\\to A = 250000\times\frac{24}{25}\times\frac{24}{25}\times\frac{24}{25}\\\\\\\to A=16\times24\times24\times24\\\\\\\implies A = 2,21,184$

Answer:

Therefore the cost of the machine after 3 years is 2,21,184

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