Math, asked by rawatanshika45127, 8 months ago

please fast Answer bcz it's urgent...​

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Answered by AntonyLigin
1

Answer:

Given,

 \frac{3 \sqrt{5}  + 2 \sqrt{3} }{3 \sqrt{5}  - 2 \sqrt{3} }

 \:  \:  \:  =  \frac{3 \sqrt{5} + 2 \sqrt{3}  }{3 \sqrt{5}  - 2 \sqrt{3} }  \times  \frac{3 \sqrt{5 } + 2 \sqrt{3}  }{3 \sqrt{5}   + 2 \sqrt{3} }

 \:  \:  \:  =  \frac{(3 \sqrt{5}  + 2 \sqrt{3} ) {}^{2} }{(3 \sqrt{5 })  {}^{2}  - (2 \sqrt{3} ) {}^{2}  }

 \:  \:  \:  =  \frac{(3 \sqrt{5}) {}^{2} + 2(3 \sqrt{5})(2 \sqrt{3}   ) + (2 \sqrt{3} ) {}^{2}  }{9(5) - 4(3)}

  \:  \:  \:  = \frac{9(5) + 12\sqrt{15}+ 4(3)}{45 - 12}

 \:  \:  \:  =  \frac{45 + 12\sqrt{15}+ 12}{33}

 \:  \:  \:  =  \frac{57+ 12\sqrt{15}}{33}

 \: \: \:  =  \frac{3(19 + 4\sqrt{15})}{33}

 \: \: \: = \frac{19 + 4\sqrt{15}}{11}

I hope you understand. Plz mark this as the BRAINLIEST.

Answered by Anonymous
1

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