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Remember, if two lines are perpendicular, the product of their gradients is -1. So if the gradient of the tangent at the point (2, 8) of the curve y = x3is 12, the gradient of the normal is -1/12, since -1/12 × 12 = -1 . hence the equation of the normalat (2,8) is 12y + x = 98 .
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