Question

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Answer 1

Explanation:

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Answer 2

$\bigstar \large \underline \purple{ \pmb{ \sf Question }}$

A concave mirror produces 3 times enlarged image of an object kept 10 cm in front of it. Where is the image located ?

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in the question we are provided with the magnification of an image which is the ratio of image distance and object distance. Also, we are given the object distance

we are asked to find the image distance.

Object Distance is always -ve.

we can use the following formula to find the required value.

$\underline{ \boxed{ \sf magnification = \frac{ - v(image \: distance)}{u(object \: distance)} }}$

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$: \implies \sf 3= \dfrac{ \cancel - v}{ \cancel- 10}$

$: \implies \sf v = 3 \times 10 = \red{30cm}$

hence, the required image is formed at a distance of 30 cm behind the mirror.

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