Question

please fast answers me
with solution​

Answer 1

all are invted hqu-wskk-rkr good purpose

and my Inst agram id is

arsalan sheikh 449

Answer 2

A(2,3),B(4,k),C(6,-3)

x1=2 ,x2=4, x3= 6

y1=3 ,y2=k ,y3= -3

1/2 [x1(y2-y3)+x2(y3-y1)+x3(y1-y2)]=0

1/2 [2(k+3)+4(-3-3)+6(3-k)=0

(k+3)-12+(9-3k)=0

k-3k+3-12+9=0

-2k=0

k=0