Question

please fast
Calculate the total number of electrons present in 1.6 g of CH4.?

Answer 1

Your answer

Molecular mass of CH4(methane) = 12+4×1

= 16

➡Moles of CH4(Methane) = 1.6/16

=0.1

➡No. of electron in 1 molecule of CH4 = 6+4

= 10 electrons

➡Total no. of electrons = 0.1 × 6.022×10^23 × 10

So, our final answer is :-

= 6.022×10^23 electrons.

Answer 2

Hey mate....

here's the answer .....

Molecular mass of methane..

12+4=16

Moles of methane...... = 1.6/16= 0.1

Electron number in 1 mol of methane...

6+4=10

Total no of moles by Avogadro's number is .... 6.022× (10)23

== 0.1 × 10 × 6 .022 × (10)23.

=

$6.022 \times 10 ^{23}$ electrons

Hope this helps❤