Math, asked by ishitareddy69, 3 months ago

please fast guys please​

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Answered by omprakashprasad979
0

Answer:

oh dear friend I don't know your answer

Answered by arpanaial06
1

By completing square method

4 {x}^{2}  + 4 \sqrt{3} x + 3 = 0

dividing \:  by  \: 4

 {x}^{2}  +  \sqrt{3} x +  \frac{3}{4} = 0

 {x}^{2}  +  \sqrt{3} x =  -  \frac{3}{4}

make  \: perfect  \: square

 {x}^{2}  +  \sqrt{3} x  +   {( \frac{ \sqrt{3} }{2} )}^{2}  =  -  \frac{3}{4}   +  \frac{3 }{4}

( {x +  \frac{ \sqrt{3} }{2} )}^{2}  = 0

( {x +  \frac{ \sqrt{3} }{2} )} = 0

x =  -  \frac{ \sqrt{3} }{2}

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