Question

Please fast . I'll give brainly

Answer 1

Heya user this is your answer..


a⁴+b⁴ can be factorized as ...

let me tell you first one another formula you have to remember :

4a^2b^2=(a^2+b^2)^2 —(a^2-b^2);

now coming to the question we get by simplification :

a^4+b^4=(a^2)^2+(b^2)^2;

=(a^2+b^2)^2–2a^2b^2;

=(a^2+b^2)^2—(1/2)[4a^2b^2];

now applying the upper mentioned simplification :

=(a^2+b^2)^2—(1/2)[(a^2+b^2)^2—(a^2-b^2)^2];

=(1/2){(a^2+b^2)^2+(a^2-b^2 )^2};

another one :

a^4+b^4=(a^2)^2+(b^2)^2;

=(a^2+b^2)^2–2a^2b^2;

=(a^2+b^2)^2—(√ 2ab)^2;

=(a^2+√ 2ab+b^2)(a^2-√ 2ab+b^2);

any of these two you can use according to your requirement .

happy for help.

hope it helps .

thank you .✌✌

Answer 2

a⁴+b⁴=(a²)²+(b²)² -2ab