Question

please fast I'll mark brainliestttt​

Answer 1

Step-by-step explanation:

i.

a = 1

b = -1

c = -10

ii.

a = 1

b = -3

c = 0

Answer 2

$\huge \underline \mathsf \red{answer}$

$2 {x}^{2} + 5x + 3 = 0$

in this a=2, b=3 & c= 5

${x}^{2} - 3x = 0$

here, a=1 since it is 1 times x², b= -3 & c=0, not shown as it is zero

Equation

x² -3x=1

2(z²-2z²)=5

y(y-2)=0

Standard form

x²-3x-1=0

2z²-4z-5=0

y²-2y=0

Coefficient

a=1 , b= -3 & c=1

a=2 , b= -3 & c= -5

a=1 , b= -2 & c=0