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Total current flowing through circuit , I=6A
R
1
=3ohm,R
2
=6ohm
(a) Combined resistance R is
1/R=1/3+1/6
1/R=3/6
R=2ohms
(b) p.d. across the combined resistance
V=IR=6×2=12V
(c) p.d. across the 3 ohm resistor = p.d. across the combined resistance
=12V.
(d) Current flowing through the 3 ohm resistor I
3 Ω
=V/R
1
=12/3=4A
(e) Current flowing through the 6 ohm resistor I
6 Ω
=V/R
2
=12/6=2A
i hope it helps^^
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