Question

please fast solve

3^3x-5=1/9x

please ​

Answer 1

$\bf\bold\purple {answer}$

33−5=19

3^{3}x-5=\frac{1}{9}x

1

Evaluate the exponent

33−5=19

{\color{#c92786}{3^{3}}}x-5=\frac{1}{9}x

27−5=19

3

Multiply by 1

27−5=19

27x-5=\frac{1x}{9}

27−5=

2

Combine multiplied terms into a single fraction

27−5=19

27x-5=\frac{1}{9}x

27−5=1

5

Simplify

Add the numbers

Find common denominator

Combine fractions with common denominator

Multiply the numbers

27=+459

27x=\frac{x+45}{9}

6

6

Multiply all terms by the same value to eliminate fraction denominators

27=+459

27x=\frac{x+45}{9}

9⋅27=9⋅+459

4

Add 

5

5

 to both sides of the equation

27−5=9

27x-5=\frac{x}{9}

27−5+5=9+5

7

Cancel multiplied terms that are in the denominator

9⋅27=9⋅+459

9 \cdot 27x=9 \cdot \frac{x+45}{9}

9⋅27=+45

9

Subtract 

x

 from both sides of the equation

243=+45

243x=x+45

243−=+45−

8

Multiply the numbers rupees 1150 price of rupees 1250 discount by shopkeeper 8 plus discount on pants

243=+45

10

Simplify

Combine like terms

Combine like terms

242=45

12

Simplify

Cancel terms that are in both the numerator and denominator

=45242

11

Divide both sides of the equation by the same term

242=45

242x=45

242242=45242

Solution

=45242